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 can you block websites on your computer???? if so how do you do it????? ...

 This is for my math homework in my textbook (www.impactmath.com). It shows a staircase patern, and a mirror image of it. So, stage 1 has 1 block. Then, a picture of stage 2 shows a block on top of it, and a block to the front, and a block to the right. Then it shows stage 3. There is a total of 7 blocks in stage three. What you did is you added (to stage 2 to make stage 3) one block to the front, one block on top of the block touching the block from stage one, one on top of everything, and the same as before. This is a link to a picture that shows what looks like stage 2. would be a block underneath the one on the top. The question is how many blocks would there be in stage 1000? This question completely stumped me. So, please help! I would really appreciate it! ...

 A block lies on a plane raised an angle thata from the horizontal. Three forces act upon the block: Fw, the force of gravity; Fn, the normal force; and Ft, the force of friction. The coefficient of friction is large enough to prevent the block from sliding. image: Because the block is not moving, the sum of the y components of the forces acting on the block must be zero. Find an expression for the sum of the y components of the forces acting on the block, using coordinate system b (shown in image). Because the block is not moving, the sum of the x components of the forces acting on the block must be zero. Find an expression for the sum of the x components of the forces acting on the block, using coordinate system b. Find an expression for the magnitude of the normal force. Express your answers in terms of some or all of the variables Fn, Ft, Fw, and thata. ...

 a small block ofmass M is realeased from rest at the top of the curved frictionless ramp. The block slides down the ramp and is moving with a speed of 3.5vnaught when it collides with a larger block of mass 1.5M at rest at the bottom of teh incline. the larger block moves to the right at a speed of 2v naught immediately after the collision express answers in terms of the given quantities and fundamental constants (A) determine height h of the ramp from which the small block isreleased (b) determine the speed of the small block after the collision (C) the larger block slides a distance D before coming to rest. Determine the value of teh coefficient of kinetic friction mew between the larger block and the surface on which it slides (d) indicate if it is a elastic or inelastic collision. so i tried it out and here are my answers if they are right let me know if not please help me (A)h=.5v^2/g (b) deltap=fdeltaT (c) mew(ma)=friction (D) inelastic ...

 Three blocks are arranged in a stack on a frictionless horizontal surface. The bottom block has a mass of 37.0 kg. A block of mass 18.0 kg sits on top of it and a 35.0 kg block sits on top of the middle block. A downward vertical force of 170 N is applied to the top block. What is the magnitude of the normal force exerted by the bottom block on the middle block? ...

 Two blocks on ramps, with friction: A marble block of mass m1 = 539.1 kg and a granite block of mass m2 = 134.4 kg are connected to each other via a rope that is directed over a pulley as shown. Both blocks are located on top of inclined planes with angles ? = 35.8 degrees and ? = 55.2 degrees, as shown. The rope glides over the pulley without friction, but the coefficients of friction of block 1 and the ramp is ?1 = 0.11, and that between block 2 and the ramp is ?2 = 0.25. (For simplicity, let us assume that the static and kinetic friction coefficients are the same in each case.) What is the acceleration of the marble block? Please note that the positive x-direction is indicated. ...

 okay, i have a block on a ramp 34 degrees above the horizontal, of mass 20kg. the ramp and block have a kinetic friction coefficient of 0.44. the block initially has a velocity of 4.6ms-1 up the ramp. i need to work out the work done on the block as it slides up to its highest point on the ramp. i can say that the velocity at its highest point is 0 ms-1. i have got a diagram drawn of the block on the ramp mg drawn straight down from the block mg sin x drawn down the slope mg cos x drawn at a right angle to the slope so apart from friction, these would be all the forces i need to consider if the block was just released to slide down the slope. BUT, it is moving up the slope with that initial velocity. so could somebody show me how i would go about finding the net force here? my thoughts are that i have to somehow find out how far the block reaches up the slope before it can go no further, but i dont know how to do this. a little explanation please? thanks. ...